document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303230>Question 303230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello again I am in the middle of a checkpoint for algebra 1A and I can not for the life of me figure this equation out. I would love you help thank you so very much!\r<BR>\n" );
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document.write( "-10/17 divided by (-3/17)\r<BR>\n" );
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document.write( "iT SAYS DIVIDE IF POSSIBLE </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217319 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -10/17 divided by (-3/17) <BR>\n" );
document.write( "The 2 minus signs cancel.<BR>\n" );
document.write( "Invert the divisor and multiply<BR>\n" );
document.write( "= (10/17)*(17/3)<BR>\n" );
document.write( "Cancel the 17<BR>\n" );
document.write( "= 10/3<BR>\n" );
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