document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303195>Question 303195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem states - Given J (-3,4) and K (-7, -2), find the magnitude of JK to the nearest tenth.  \r<BR>\n" );
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document.write( "Please help me with this.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217309 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume you are talking about vectors.\r<BR>\n" );
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document.write( "Let |JK| = the magnitude that we are seeking.\r<BR>\n" );
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document.write( "We use the distance formula.\r<BR>\n" );
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document.write( "|JK| = sqrt{(-7 -(-3))^2 + (-2 - 4)^2}\r<BR>\n" );
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document.write( "|JK| = sqrt{(-7 + 3)^2 + (-6)^2}\r<BR>\n" );
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document.write( "|JK| = sqrt{(-4)^2 + 36}\r<BR>\n" );
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document.write( "|JK| = sqrt{16 + 36}\r<BR>\n" );
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document.write( "|JK| = sqrt{52}\r<BR>\n" );
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document.write( "|JK| = 7.2111102551\r<BR>\n" );
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document.write( "We round this decimal to the tenths place and get\r<BR>\n" );
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document.write( "|JK| = 7.2 </SPAN>\n" );
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