document.write( "Question 4612: Tim is driving a truck to chicago. He is driving at 55 miles per hour and has to hit the brakes because of heavy traffic. His truck slows at the rate of 2 miles per hour for every 3 seconds. How fast will he be traveling 10 seconds after he hits the brakes? \n" ); document.write( "

Algebra.Com's Answer #2173 by xcentaur(357) $\"\"$ $\"About$

You can put this solution on YOUR website!
Time=10 seconds
\n" ); document.write( "Rate of deacceleration=2 miles per 3 seconds\r
\n" ); document.write( "\n" ); document.write( "Original Speed=55 mph
\n" ); document.write( "Man hits brakes.
\n" ); document.write( "-----
\n" ); document.write( "After 3 seconds=>deacc = 2 mph
\n" ); document.write( "Speed=55-2=53 mph
\n" ); document.write( "-----
\n" ); document.write( "After another 3 seconds=>deacc = 2 mph
\n" ); document.write( "Speed=53-2=51 mph
\n" ); document.write( "-----
\n" ); document.write( "After another 3 seconds=>deacc = 2 mph
\n" ); document.write( "Speed=51-2=49 mph
\n" ); document.write( "-----
\n" ); document.write( "After 9 seconds,speed=49 mph
\n" ); document.write( "Last one second,deacc = 2/3 mph
\n" ); document.write( "Hence speed=
\n" ); document.write( "=49-2/3
\n" ); document.write( "=48.33 mph\r
\n" ); document.write( "\n" ); document.write( "------
\n" ); document.write( "Ans: 48.33 mph
\n" ); document.write( "xcentaur-at-hotmail-dot-com
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