document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303182>Question 303182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving 2 equations: x-3y=4<BR>\n" );
document.write( "(Trying to find x & y) 2x+y=6     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217281 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> many methods for solution\r<BR>\n" );
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document.write( "adding 3y to first equation ___ x = 3y + 4\r<BR>\n" );
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document.write( "substituting into second equation ___ 2(3y + 4) + y = 6 ___ 7y + 8 = 6 ___ y = -2/7\r<BR>\n" );
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document.write( "substituting ___ x = 3(-2/7) + 4 = 22/7\r<BR>\n" );
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document.write( "multiplying first equation by 2 ___ 2x - 6y = 8\r<BR>\n" );
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document.write( "subtracting second equation ___ -7y = 2 ___ y = -2/7\r<BR>\n" );
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document.write( "substituting ___ x - 3(-2/7) = 4 ___ x = 22/7 </SPAN>\n" );
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