document.write( "Question 303174: Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?
\n" ); document.write( "Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1\r
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\n" ); document.write( "\n" ); document.write( "g(x) = ln(x + 2)\r
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Algebra.Com's Answer #217276 by CharlesG2(834)\"\" \"About 
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Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?
\n" ); document.write( "Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1 \r
\n" ); document.write( "\n" ); document.write( "g(x) = ln(x + 2) \r
\n" ); document.write( "\n" ); document.write( "Am guessing that \"Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?\" is a mistake.
\n" ); document.write( "So evaluating \"Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1\" instead.\r
\n" ); document.write( "\n" ); document.write( "g(0) = ln(0 + 2) = ln 2
\n" ); document.write( "g(0.25) = ln(0.25 + 2) = ln(2.25) = ln(9/4) = ln 9 - ln 4
\n" ); document.write( "(by logarithmic division rule)
\n" ); document.write( "g(0.5) = ln(0.5 + 2) = ln(2.5) = ln(5/2) = ln 5 - ln 2
\n" ); document.write( "g(0.75) = ln(0.75 + 2) = ln(2.75) = ln(11/4) = ln 11 - ln 4
\n" ); document.write( "g(1) = ln(1 + 2) = ln 3
\n" ); document.write( "g(1.25) = ln(3.25) = ln(13/4) = ln 13 - ln 4
\n" ); document.write( "g(1.5) = ln(3.5) = ln(7/2) = ln 7 - ln 2
\n" ); document.write( "g(1.75) = ln(3.75) = ln(15/4) = ln 15 - ln 4
\n" ); document.write( "if you want undefined values look for x <= -2, as x > -2 is all defined\r
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