document.write( "Question 303143: Jack is twice as old as Jill but in five years time he will only be one and half times as old. How old is Jack and Jill now? \n" ); document.write( "
Algebra.Com's Answer #217245 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jack is twice as old as Jill \n" ); document.write( "Ja = 2Ji \n" ); document.write( ": \n" ); document.write( "but in five years time he will only be one and half times as old. \n" ); document.write( "Ja + 5 = 1.5(Ji+5) \n" ); document.write( "Ja + 5 = 1.5Ji + 7.5 \n" ); document.write( "Ja = 1.5Ji + 7.5 - 5 \n" ); document.write( "Ja = 1.5Ji + 2.5 \n" ); document.write( "Replace Ja with 2Ji \n" ); document.write( "2Ji = 1.5Ji + 2.5 \n" ); document.write( "2Ji - 1.5Ji = 2.5 \n" ); document.write( ".5Ji = 2.5 \n" ); document.write( "Mult both sides by 2 \n" ); document.write( "Ji = 5 \n" ); document.write( ": \n" ); document.write( "I'll let you find Ja's age\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |