document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303112>Question 303112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i work out what X is if the Hypotenuse is 25, on side is x and the other is 2x????     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217232 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217232\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one side is x<BR>\n" );
document.write( "the other side = 2x\r<BR>\n" );
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document.write( "hypotenuse = 25\r<BR>\n" );
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document.write( "side1^2+side2^2 = hypotenuse^2\r<BR>\n" );
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document.write( "x^+(2x)^2=25^2\r<BR>\n" );
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document.write( "x^2+4x^2=625\r<BR>\n" );
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document.write( "5x^2=625<BR>\n" );
document.write( "x^2=625/5\r<BR>\n" );
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document.write( "x^2=125\r<BR>\n" );
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document.write( "x=sqrt125\r<BR>\n" );
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document.write( "11.18 units\r<BR>\n" );
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document.write( " </SPAN>\n" );
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