document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=303022>Question 303022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 312  yards. If the width of the field is 72 yards, what is its length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #217204 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=217204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 312=2L+2W<BR>\n" );
document.write( "312=L+2*72<BR>\n" );
document.write( "312=2L+144<BR>\n" );
document.write( "2L=312-144<BR>\n" );
document.write( "2L=168<BR>\n" );
document.write( "L=168/2<BR>\n" );
document.write( "L=84 YDS. ANS FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "312=2*84+2*72<BR>\n" );
document.write( "312=168+144<BR>\n" );
document.write( "312=312 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );