document.write( "Question 302973: Smith travels 45 miles going East from the center of the town and jones travels 70 miles going west from the same point. If Jones averages 5 miles per hour more than Smith and his trip1/2 hour longer than Smith. How fast was each of them traveling. \n" ); document.write( "
Algebra.Com's Answer #217177 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Smith travels 45 miles going East from the center of the town and jones travels 70 miles going west from the same point. If Jones averages 5 miles per hour more than Smith and his trip1/2 hour longer than Smith. How fast was each of them traveling.\r \n" ); document.write( "\n" ); document.write( "let smith's rate be x mph\r \n" ); document.write( "\n" ); document.write( "time taken by smith = 45/x hours\r \n" ); document.write( "\n" ); document.write( "jones's rate = x+5 mph\r \n" ); document.write( "\n" ); document.write( "time taken by jones = 70/ x+5\r \n" ); document.write( "\n" ); document.write( "70 /x+5 - 45/x = 1/2\r \n" ); document.write( "\n" ); document.write( "70x-45x-225=1/2 *x(x+5 )\r \n" ); document.write( "\n" ); document.write( "2(25x-225)=x^2+5x\r \n" ); document.write( "\n" ); document.write( "50x-450=x^2+5x\r \n" ); document.write( "\n" ); document.write( "x^2-50x+5x+450=0\r \n" ); document.write( "\n" ); document.write( "x^2-45x+450=0 \r \n" ); document.write( "\n" ); document.write( "x^2-30x-15x+450=0\r \n" ); document.write( "\n" ); document.write( "x(x-30)-15(x-30)=0\r \n" ); document.write( "\n" ); document.write( "(x-30)(x-15)=0\r \n" ); document.write( "\n" ); document.write( "x= 30 OR 15 mph\r \n" ); document.write( "\n" ); document.write( "Ananth\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |