document.write( "Question 302589: Hi,\r
\n" ); document.write( "\n" ); document.write( "Can anyone please help me with this one, i'm struggling a bit.\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
\n" ); document.write( "\n" ); document.write( "Solve for P;\r
\n" ); document.write( "\n" ); document.write( "0.29 = 100 X 1 SQRT(0.0029(1 - 0.0029)P) \n" ); document.write( "

Algebra.Com's Answer #216993 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"0.29+=+100%2Asqrt%280.0029%281+-+0.0029%29P%29\"$
\n" ); document.write( " $\"0.0029=sqrt%280.0029%280.9971%29P%29\"$
\n" ); document.write( " $\"0.00000841=0.00289159P\"$
\n" ); document.write( " $\"P=0.0029084\"$
\n" ); document.write( " \n" ); document.write( "

\n" );