document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=302591>Question 302591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log5 1/125 = x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216964 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log5 1/125 = x\r<BR>\n" );
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document.write( "Rewrite log5 1/125  : \r<BR>\n" );
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document.write( "1/125 = 125^-1\r<BR>\n" );
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document.write( "This gives: \r<BR>\n" );
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document.write( "log 5 (125^-1) , bring down the power \r<BR>\n" );
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document.write( "-1 (log5 125) , rewrite 125 in term of power of 5 \r<BR>\n" );
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document.write( "-1 (log5 (5^3), again bring down the power\r<BR>\n" );
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document.write( "(-1*3)(log5 5), note log5 5 = 1 \r<BR>\n" );
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document.write( "Answer: x = -3  </SPAN>\n" );
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