document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35550>Question 35550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please provide me an explanation of why the change of base formula can be proven. I need to provide proof why this works and I am having trouble finding the answer!!! Thank you for any help you provide. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21696 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let y=log(baseA)B<BR>\n" );
document.write( "Then A^y=B<BR>\n" );
document.write( "Take the log(baseC) of both sides to get:<BR>\n" );
document.write( "log(baseC)A^y=log(baseC)B<BR>\n" );
document.write( "Using the law of logs which says logA^n=nlogA you get:<BR>\n" );
document.write( "y(log(baseC)A = log(baseC)B<BR>\n" );
document.write( "y= [log(baseC)B/[log(baseC)A}<BR>\n" );
document.write( "Therefore log(baseA)B = [log(baseC)B]/[log(baseC)A]<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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