document.write( "Question 302564: 2m^3+3m^2-32m-48
\n" ); document.write( "polynomial factoring completely \n" ); document.write( "
Algebra.Com's Answer #216940 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"2m%5E3%2B3m%5E2-32m-48\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%282m%5E3%2B3m%5E2%29%2B%28-32m-48%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"m%5E2%282m%2B3%29-16%282m%2B3%29\" Factor out the GCF \"m%5E2\" out of the first group. Factor out the GCF \"-16\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28m%5E2-16%29%282m%2B3%29\" Since we have the common term \"2m%2B3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28m%2B4%29%28m-4%29%282m%2B3%29\" Factor \"m%5E2-16\" to get \"%28m%2B4%29%28m-4%29\" (use difference of squares formula)\r
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\n" ); document.write( "\n" ); document.write( "So \"2m%5E3%2B3m%5E2-32m-48\" factors to \"%28m%2B4%29%28m-4%29%282m%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"2m%5E3%2B3m%5E2-32m-48=%28m%2B4%29%28m-4%29%282m%2B3%29\"
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