document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=302517>Question 302517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the altitude is 5 less than the base. the area is 42 sq.inches.               find the base and altitude </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216907 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the base be x\r<BR>\n" );
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document.write( "altitude = x-5\r<BR>\n" );
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document.write( "Area of triangle = 1/2 * base * altitude\r<BR>\n" );
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document.write( "=1/2 *x*(x-5) = 42\r<BR>\n" );
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document.write( "x^2-5x=84\r<BR>\n" );
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document.write( "x^2-5x-84=0\r<BR>\n" );
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document.write( "x^2-12x+7x-84=0\r<BR>\n" );
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document.write( "x(x-12)+7(x-12)=0\r<BR>\n" );
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document.write( "(x-12)(x+7)=0\r<BR>\n" );
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document.write( "x=12 OR x=-7\r<BR>\n" );
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document.write( "So  the base is 12\r<BR>\n" );
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document.write( "Altitude = 12-5=7\r<BR>\n" );
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document.write( " </SPAN>\n" );
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