document.write( "Question 302332: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 28 square feet, find the lengths of the sides of the poster and the sign? \n" ); document.write( "
Algebra.Com's Answer #216903 by ankor@dixie-net.com(22740)\"\" \"About 
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A square poster has sides measuring 2 feet less than the sides of a square sign.
\n" ); document.write( " If the difference between their areas is 28 square feet, find the lengths of the sides of the poster and the sign?
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\n" ); document.write( "Let x = side of the poster
\n" ); document.write( "then
\n" ); document.write( "(x+2) = side of the sign
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\n" ); document.write( "Sign area - poster area = 28 sq/ft
\n" ); document.write( "(x+2)^2 - x^2 = 28
\n" ); document.write( "x^2 + 4x + 4 - x^2 = 28
\n" ); document.write( "x^2 - x^2 + 4x = 28 - 4
\n" ); document.write( "4x = 24
\n" ); document.write( "x = \"24%2F4\"
\n" ); document.write( "x = 6 ft is the side of the poster
\n" ); document.write( "and
\n" ); document.write( "6 + 3 = 8 ft is the side of the sign
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\n" ); document.write( "Check solution
\n" ); document.write( "8^2 - 6^2 =
\n" ); document.write( "64 - 36 = 28
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