document.write( "Question 35538: Hello! My college professor told me the answer to this problem. The answer is:
\n" ); document.write( "x + y/ x - y. I do not know how to work the problem, and I need to know! The problem is 1/x + 1/y/ 1/y - 1/x. Please simplify the expression, and show all work. Thank you very much for the help!
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Algebra.Com's Answer #21689 by elima(1433)\"\" \"About 
You can put this solution on YOUR website!
Bare with me and I will try to explain;
\n" ); document.write( "\"%281%2Fx+%2B+1%2Fy%29%2F%281%2Fy+-1%2Fx%29\"
\n" ); document.write( "When you add or subtract fractions you need LCD;
\n" ); document.write( "so we will start with the numerator;
\n" ); document.write( "\"1%2Fx%2B1%2Fy\"
\n" ); document.write( "multiply the first side by y; and the second by x;
\n" ); document.write( "\"%28y%291%2F%28y%29x%2B%28x%291%2F%28x%29y\";
\n" ); document.write( "\"y%2Fxy%2Bx%2Fxy\"
\n" ); document.write( "now you have common denominators so you can add;
\n" ); document.write( "\"%28y%2Bx%29%2Fxy\"; now do the same thing with the denominator;
\n" ); document.write( "1/y -1/x
\n" ); document.write( "multiply the first side by x and the second by y;
\n" ); document.write( "\"%28x%291%2F%28x%29y\"-\"%28y%291%2F%28y%29x\";
\n" ); document.write( "\"x%2Fxy-y%2Fxy\"
\n" ); document.write( "subtract;
\n" ); document.write( "\"%28x-y%29%2Fxy\"
\n" ); document.write( "Now lets but the equation back together;
\n" ); document.write( "\"%28%28y%2Bx%29%2F%28xy%29%29%2F%28%28x-y%29%2Fxy%29\"
\n" ); document.write( "Now, when you divide fractions the second term is inversed(reciprocal), and you mulitply;
\n" ); document.write( "\"%28%28y%2Bx%29%2Fxy%29\"*\"%28xy%2F%28x-y%29%29\"
\n" ); document.write( "Now cross cancel;
\n" ); document.write( "\"%28%28x%2By%29%2Fxy%29+%2A%28xy%2F%28x-y%29%29\"
\n" ); document.write( "\"%28x%2By%29%2F%28x-y%29\"
\n" ); document.write( "Hope you were able to bare with me and understand
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