document.write( "Question 302496: The width of a rectangle is 2 ft less then the length. The area is 3 ft ^2. Find the length and the width \n" ); document.write( "
Algebra.Com's Answer #216880 by mananth(16946)\"\" \"About 
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let the length be x\r
\n" ); document.write( "\n" ); document.write( "width will be x-2\r
\n" ); document.write( "\n" ); document.write( "area of rectangle = L *W\r
\n" ); document.write( "\n" ); document.write( "x(x-2)= 3\r
\n" ); document.write( "\n" ); document.write( "x^2-2x=3\r
\n" ); document.write( "\n" ); document.write( "x^2-2x-3=0\r
\n" ); document.write( "\n" ); document.write( "x^2-3x+x-3=0\r
\n" ); document.write( "\n" ); document.write( "x(x-3)+1(x-3)=0\r
\n" ); document.write( "\n" ); document.write( "(x+1)(x-3)=0\r
\n" ); document.write( "\n" ); document.write( "x=3 OR x=-1\r
\n" ); document.write( "\n" ); document.write( "length cant be negative \r
\n" ); document.write( "\n" ); document.write( "so length = 3\r
\n" ); document.write( "\n" ); document.write( "width = x-2
\n" ); document.write( "=3-2\r
\n" ); document.write( "\n" ); document.write( "=1\r
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