document.write( "Question 302437: The width of a rectangle is 7 feet longer than the length. If the area is 330 square feet, find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #216836 by london maths tutor(243) $\"\"$ $\"About$

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Area of a rectangle = width x length \r
\n" ); document.write( "\n" ); document.write( "let's width be w and length be L\r
\n" ); document.write( "\n" ); document.write( "w = 7 + L \r
\n" ); document.write( "\n" ); document.write( "Area : L(7+L) = 330 \r
\n" ); document.write( "\n" ); document.write( " $\"7L+%2B+L%5E2+=+330\"$
\n" ); document.write( " $\"+L%5E2+%2B7L+-+330+=+0+\"$
\n" ); document.write( " $\"+%28L+-+15%29%28L+%2B+2%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "L -15 = 0 , L = 15 ft or L + 2 = 0 L = -2ft (N/A)\r
\n" ); document.write( "\n" ); document.write( "Length = 15 ft
\n" ); document.write( "Therefore width = 7 + 15 = 22 ft \r
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