document.write( "Question 4651: urgent....need help?\r
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document.write( "the difference of two numbers is 11, and their product is 42. Find these numbers.\r
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document.write( "choices:
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document.write( "a. -14 and 3
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document.write( "b. -3 and 14
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document.write( "c. pair -14 and 3, -3 and 14
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document.write( "d. pair -14 and 3, 3 and 14\r
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document.write( "respond asap \n" );
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Algebra.Com's Answer #2168 by Earlsdon(6294) ![]() You can put this solution on YOUR website! Let the two numbers be x and y:\r \n" ); document.write( "\n" ); document.write( "Then: \n" ); document.write( "x - y = 11 Rewrite this as: x = 11 + y and substitute into the 2nd equation. \n" ); document.write( "xy = 42\r \n" ); document.write( "\n" ); document.write( "(11 + y)y = 42 Simplify. \n" ); document.write( "y^2 + 11y - 42 = 0 Solve by factoring.\r \n" ); document.write( "\n" ); document.write( "(y + 14)(y - 3) = 0 Apply the zero products principle.\r \n" ); document.write( "\n" ); document.write( "y - 3 = 0; y = 3 or \n" ); document.write( "y + 14 = 0; y = -14 \r \n" ); document.write( "\n" ); document.write( "x = 11 + y \n" ); document.write( "x = 11 + 3 = 14 or \n" ); document.write( "x = 11 + (-14) = -3\r \n" ); document.write( "\n" ); document.write( "The numbers are: 14 and 3 or -3 and -14\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " 14-3 = 11 and 14(3) = 42 or \n" ); document.write( "-3-(-14) = 11 and (-3)(-14) = 42 \n" ); document.write( " \n" ); document.write( " |