document.write( "Question 302209: 2. Bacteria grow by cell division. If each cell divides into 2 in every 2 minutes how many cells will exist after 32 minutes? Assume there was only one cell at the beginning \n" ); document.write( "
Algebra.Com's Answer #216734 by nerdybill(7384)\"\" \"About 
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2. Bacteria grow by cell division. If each cell divides into 2 in every 2 minutes how many cells will exist after 32 minutes? Assume there was only one cell at the beginning
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\n" ); document.write( "C(t) = Co*e^(rt)
\n" ); document.write( "where
\n" ); document.write( "C(t) number of cells after t time
\n" ); document.write( "Co initial number of cells
\n" ); document.write( "r is rate of growth
\n" ); document.write( "t is time in minutes
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\n" ); document.write( "To determine r:
\n" ); document.write( "We use:\"each cell divides into 2 in every 2 minutes\"
\n" ); document.write( "C(t) = Co*e^(rt)
\n" ); document.write( "2 = 1*e^(r*2)
\n" ); document.write( "2 = e^(r*2)
\n" ); document.write( "ln(2) = r*2
\n" ); document.write( "ln(2)/2 = r
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\n" ); document.write( "Our equation is now:
\n" ); document.write( "C(t) = e^(ln(2)t/2)
\n" ); document.write( "Now, we can answer \"how many cells will exist after 32 minutes?\"
\n" ); document.write( "C(32) = e^(ln(2)(32)/2)
\n" ); document.write( "C(32) = e^(ln(2)(16))
\n" ); document.write( "C(32) = 65536
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