document.write( "Question 302020: solve each system using the substitution method.
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document.write( "x-2y=7
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document.write( "3x-21=6y \n" );
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Algebra.Com's Answer #216717 by london maths tutor(243)![]() ![]() You can put this solution on YOUR website! x-2y=7 ... equation 1 \n" ); document.write( "3x-21=6y ... equation 2\r \n" ); document.write( "\n" ); document.write( "Let's x = 1 \r \n" ); document.write( "\n" ); document.write( "x-2y = 7 \n" ); document.write( "1 - 2y = 7 \n" ); document.write( "-2y = 7 -1 \n" ); document.write( "-2y = 6 \n" ); document.write( "y = -3\r \n" ); document.write( "\n" ); document.write( "Put y = -3 and x = 1 into equation 2\r \n" ); document.write( "\n" ); document.write( "3x - 21 = 6y \n" ); document.write( "3x - 6y = 21 \n" ); document.write( "3(1) - 6(-3) = 21 \n" ); document.write( "3 -(-18) = 21 \n" ); document.write( "3 + 18 = 21 \n" ); document.write( "21 = 21 \r \n" ); document.write( "\n" ); document.write( "Therefore, x = 1 and y = -3 \n" ); document.write( " |