document.write( "Question 302020: solve each system using the substitution method.
\n" ); document.write( "x-2y=7
\n" ); document.write( "3x-21=6y
\n" ); document.write( "

Algebra.Com's Answer #216717 by london maths tutor(243)\"\" \"About 
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x-2y=7 ... equation 1
\n" ); document.write( "3x-21=6y ... equation 2\r
\n" ); document.write( "\n" ); document.write( "Let's x = 1 \r
\n" ); document.write( "\n" ); document.write( "x-2y = 7
\n" ); document.write( "1 - 2y = 7
\n" ); document.write( "-2y = 7 -1
\n" ); document.write( "-2y = 6
\n" ); document.write( "y = -3\r
\n" ); document.write( "\n" ); document.write( "Put y = -3 and x = 1 into equation 2\r
\n" ); document.write( "\n" ); document.write( "3x - 21 = 6y
\n" ); document.write( "3x - 6y = 21
\n" ); document.write( "3(1) - 6(-3) = 21
\n" ); document.write( "3 -(-18) = 21
\n" ); document.write( "3 + 18 = 21
\n" ); document.write( "21 = 21 \r
\n" ); document.write( "\n" ); document.write( "Therefore, x = 1 and y = -3
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