document.write( "Question 302185: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
\n" ); document.write( "A water rocket is launched upward with an initial velocity of 48 ft/sec. Its height h, in feet, after t seconds is given by h = 48t - 16t2. After how many seconds will the height of the rocket be 20 feet? Show work
\n" ); document.write( "can some one please helpme with this
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Algebra.Com's Answer #216708 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
h = 48t - 16t2
\n" ); document.write( "Set h = 20 and solve for t
\n" ); document.write( "20 = 48t - 16t2
\n" ); document.write( "-16t^2 + 48t - 20 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-16x%5E2%2B48x%2B-20+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2848%29%5E2-4%2A-16%2A-20=1024\".
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\n" ); document.write( " Discriminant d=1024 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-48%2B-sqrt%28+1024+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2848%29%2Bsqrt%28+1024+%29%29%2F2%5C-16+=+0.5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2848%29-sqrt%28+1024+%29%29%2F2%5C-16+=+2.5\"
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\n" ); document.write( " Quadratic expression \"-16x%5E2%2B48x%2B-20\" can be factored:
\n" ); document.write( " \"-16x%5E2%2B48x%2B-20+=+%28x-0.5%29%2A%28x-2.5%29\"
\n" ); document.write( " Again, the answer is: 0.5, 2.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B48%2Ax%2B-20+%29\"

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\n" ); document.write( "\n" ); document.write( "t = x-axis, h = y-axis
\n" ); document.write( "It's a 20 ft going up, then again coming down.
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