document.write( "Question 302004: solve:
\n" ); document.write( "12^(2x)=100
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Algebra.Com's Answer #216696 by london maths tutor(243)\"\" \"About 
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12^(2x)=100\r
\n" ); document.write( "\n" ); document.write( "the log base is 12, this gives: \r
\n" ); document.write( "\n" ); document.write( "log12 (100) = 2x
\n" ); document.write( "log12 (10^2) = 2x
\n" ); document.write( "2*log12 (10)= 2x
\n" ); document.write( "log12 (10) = x
\n" ); document.write( "x = 0.927
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