document.write( "Question 302176: A motarboat can maintain a constant speed of 50 mph relative to the water. the boat makes a trip upstream to a certain point in 51 minutes; the return trip takes 49 minutes. what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #216692 by mananth(16946)\"\" \"About 
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upstream it takes 51 minutes\r
\n" ); document.write( "\n" ); document.write( "let the speed of current be x mph\r
\n" ); document.write( "\n" ); document.write( "speed of boat will be 50-x\r
\n" ); document.write( "\n" ); document.write( "speed * time = distance
\n" ); document.write( "=(50-x) * 51/60 \r
\n" ); document.write( "\n" ); document.write( "downstream it takes 49 minutes\r
\n" ); document.write( "\n" ); document.write( "speed of boat = 50+x\r
\n" ); document.write( "\n" ); document.write( "Distance = (50+x)*49/60\r
\n" ); document.write( "\n" ); document.write( "Since the distance traveled both ways is the same \r
\n" ); document.write( "\n" ); document.write( "(50-x)*51/60 = (50+x)*49/60\r
\n" ); document.write( "\n" ); document.write( "(50-x)*51 = (50+x)*49\r
\n" ); document.write( "\n" ); document.write( "2550-51x=2450+49x\r
\n" ); document.write( "\n" ); document.write( "2550-2450=51x+49x\r
\n" ); document.write( "\n" ); document.write( "100=100x\r
\n" ); document.write( "\n" ); document.write( "x=1 mph which is the speed of the current\r
\n" ); document.write( "\n" ); document.write( "Ananth\r
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