document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35518>Question 35518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:  (1/8) to the 2x-1 (2x-1 is the exponent) = 8 to the x-1 (x-1 is the exponent. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21669 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/8)^(2x-1) = (8)^(x-1)<BR>\n" );
document.write( "(8^(-1))^(2x-1) = (8)^(x-1)<BR>\n" );
document.write( "(8)^(-2x+1)=8^(x-1)<BR>\n" );
document.write( "-2x + 1 = x - 1<BR>\n" );
document.write( "-3x = -2<BR>\n" );
document.write( "x = 2/3 </SPAN>\n" );
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