document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=302147>Question 302147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> express as a sum, difference, and a product of logarithms, without using exponents.      log base 18 7squareroot of x/y       </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216686 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note that square root is to the power to 1/2\r<BR>\n" );
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document.write( "log base 18 7squareroot of x/y<BR>\n" );
document.write( "= log18 (7) + log18 [(x/y)^(1/2)]<BR>\n" );
document.write( "= log18 (7) + (1/2)*log 18 (x/y)<BR>\n" );
document.write( "= log18 (7) + (1/2)*log18 (x) - (1/2)*log18 (y)\r<BR>\n" );
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