document.write( "Question 302024: a photo is 3 inches longer than wide and has a 2 inch border around the photo making the total area of photo and border 108inches^2 What are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #216666 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the width of the photo be x\r \n" ); document.write( "\n" ); document.write( "length will be x+3\r \n" ); document.write( "\n" ); document.write( "the border is 2\" on all sides\r \n" ); document.write( "\n" ); document.write( "increase in length and width incheswil l be by 4\r \n" ); document.write( "\n" ); document.write( "including border the \r \n" ); document.write( "\n" ); document.write( "width will be x+4\r \n" ); document.write( "\n" ); document.write( "and length will be x+3 +4 = x+7\r \n" ); document.write( "\n" ); document.write( "(x+4)(x+7 ) =108\r \n" ); document.write( "\n" ); document.write( "x^2+7x+4x+28 =108\r \n" ); document.write( "\n" ); document.write( "x^2+11x+28-108=0\r \n" ); document.write( "\n" ); document.write( "x^2+11x-80 =0\r \n" ); document.write( "\n" ); document.write( "x^2+16x-5x-80=0\r \n" ); document.write( "\n" ); document.write( "x(x+16)-5(x+16)=0\r \n" ); document.write( "\n" ); document.write( "(x-5)(x+16)=0\r \n" ); document.write( "\n" ); document.write( "x=5 OR x=-16\r \n" ); document.write( "\n" ); document.write( "x=5 inches is the width of the photo\r \n" ); document.write( "\n" ); document.write( "the length will be 8 inches\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |