document.write( "Question 302031: An express train leaves New York at 3pm and reaches Boston at 6pm. A slow train leaves Boston at 1.30pm and arrives at New York at 6pm. If both trains travel at constant speeds, at what time do they meet? \n" ); document.write( "
Algebra.Com's Answer #216651 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
An express train leaves New York at 3pm and reaches Boston at 6pm.
\n" ); document.write( " A slow train leaves Boston at 1.30pm and arrives at New York at 6pm.
\n" ); document.write( " If both trains travel at constant speeds, at what time do they meet?
\n" ); document.write( ":
\n" ); document.write( "From the given information:
\n" ); document.write( "Express travel time = 3 hrs
\n" ); document.write( "Slow train travel time = 4.5 hrs
\n" ); document.write( ":
\n" ); document.write( "Let d = dist from N.Y. to Boston
\n" ); document.write( ":
\n" ); document.write( "\"d%2F3\" = speed of express
\n" ); document.write( "\"d%2F4.5\" = speed of the slow train
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of express when they meet
\n" ); document.write( "then
\n" ); document.write( "(t+1.5) = travel time of the slow train when they meet
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Dist of each train = the total dist
\n" ); document.write( "\"d%2F3\"t + \"d%2F4.5\"(t+1.5) = d
\n" ); document.write( "multiply thru by 9 to get rid of the denominators, results:
\n" ); document.write( "3dt + 2d(t+1.5) = 9d
\n" ); document.write( "3dt + 2dt + 3d = 9d
\n" ); document.write( "5dt + 3d = 9d
\n" ); document.write( "divide thru by d
\n" ); document.write( "5t + 3 = 9
\n" ); document.write( "5t = 9 - 3
\n" ); document.write( "5t = 6
\n" ); document.write( "t = \"6%2F5\"
\n" ); document.write( "t = 1.2 hrs, which is 1 hr 12 min
\n" ); document.write( ":
\n" ); document.write( "3:00 + 1:12 = 4:12 pm the trains meet
\n" ); document.write( "
\n" ); document.write( "
\n" );