document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35500>Question 35500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the vector u has magnitude 10 and bearing 200 degrees. vector v has magnitude 8 and bearing 35 degrees. choose the correct magnitude of u-v and its bearings. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21665 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the vector u has magnitude 10 and bearing 200 degrees. vector v has magnitude 8 and bearing 35 degrees. choose the correct magnitude of u-v and its bearings.<BR>\n" );
document.write( "ONE STANDARD METHOD IS TO DECOMPOSE EACH VECTOR INTO ITS COMPONENTS AND THEN ADD OR SUBTRACT OR WHATEVER IS NEEDED<BR>\n" );
document.write( "U=10COS(200)*i+10SIN(200)*j=-9.403i-3.404j<BR>\n" );
document.write( "V=8COS(35)*i+8SIN(35)*j=6.555i+4.587j<BR>\n" );
document.write( "U-V=-15.9576i-7.99j<BR>\n" );
document.write( "|U-V|=SQRT{(-15.9576)^2+(-7.99)^2}=17.84622<BR>\n" );
document.write( "TAN(BEARING)=0.5008<BR>\n" );
document.write( "BEARING=26.6 DEGREES </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );