document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=302074>Question 302074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	The product of the ages of A and B is 104. If thrice the age of B is less than A's age by 11 years. Find the B's age.thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216607 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AB=104<BR>\n" );
document.write( "3B=A-11 OR A=3B+11<BR>\n" );
document.write( "(3B-11)B=104<BR>\n" );
document.write( "3B^2-11B-104=0<BR>\n" );
document.write( "(3B+13)(B-8)=0<BR>\n" );
document.write( "B-8=0<BR>\n" );
document.write( "B=8 AGE OF B.<BR>\n" );
document.write( "A*8104<BR>\n" );
document.write( "A=104/8=13 AGO OF A.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "13=3*8-11<BR>\n" );
document.write( "13=23=11<BR>\n" );
document.write( "13=13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );