document.write( "Question 4660: I am stuck on this problem, please help!
\n" ); document.write( "Complete the ordered pair so that is satisfies the given equation.
\n" ); document.write( "a=b^2+4b+5 (-2, ??) (??,2)
\n" ); document.write( "Thanks in advance for your help!! \n" ); document.write( "
Algebra.Com's Answer #2166 by Earlsdon(6294)\"\" \"About 
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Let's take the first given ordered pair, (-2, ?) which you could write in more familiar terms (x, y) or (-2, y) and rewrite the equation in more familiar notation:
\n" ); document.write( " y = x^2 + 4x + 5 Substitute x = -2 and solve for y:\r
\n" ); document.write( "\n" ); document.write( "y = (-2)^2 + 4(-2) + 5
\n" ); document.write( "y = 4 - 8 + 5
\n" ); document.write( "y = 1 \r
\n" ); document.write( "\n" ); document.write( "The first ordered pair is (-2, 1)\r
\n" ); document.write( "\n" ); document.write( "Now the second given ordered pair, (x, 2):\r
\n" ); document.write( "\n" ); document.write( "y = x^2 + 4x + 5 Substitute y = 2 and solve for x.
\n" ); document.write( "2 = x^2 + 4x + 5 Subtract 2 from both sides.
\n" ); document.write( "x^2 + 4x + 3 = 0 Factor.
\n" ); document.write( "(x + 1)(x + 3) = 0 Apply the zero products principle.\r
\n" ); document.write( "\n" ); document.write( "x + 1 = 0; x = -1 or x + 3 = 0; x = -3\r
\n" ); document.write( "\n" ); document.write( "The second ordered pair is: (-1, 2) or (-3, 2) \n" ); document.write( "
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