document.write( "Question 301967: I know the answer to this problem, but I need help on how to actually find the answer. The problem is:\r
\n" ); document.write( "\n" ); document.write( "If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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Algebra.Com's Answer #216536 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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\n" ); document.write( "Steven Data:
\n" ); document.write( "time = 5 minutes/job ; rate = 1/5 job/min
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\n" ); document.write( "Sue Data:
\n" ); document.write( "time = 10 min/job ; rate = 1/10 job/min
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\n" ); document.write( "Jack Data:
\n" ); document.write( "time = 15 min/job ; rate = 1/15 job/min
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\n" ); document.write( "Together Data:
\n" ); document.write( "time = x min/job ; rate = 1/x job/min
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate + rate = together rate
\n" ); document.write( "1/5 + 1/10 + 1/15 = 1/x
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\n" ); document.write( "Multiply thru by 30x to get:
\n" ); document.write( "6x + 3x + 2x = 30
\n" ); document.write( "11x = 30
\n" ); document.write( "x = 30/11 = 2.73 minutes to mix 20 drinks
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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