document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301952>Question 301952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> number of donuts                         total price  \r<BR>\n" );
document.write( "\n" );
document.write( "1                                          $0.40 <BR>\n" );
document.write( "       <BR>\n" );
document.write( "box of 6                                   $1.89  <BR>\n" );
document.write( "         <BR>\n" );
document.write( "box of 12                                  $3.59  \r<BR>\n" );
document.write( "\n" );
document.write( "  \r<BR>\n" );
document.write( "\n" );
document.write( "1)<BR>\n" );
document.write( "of the following  ,which is the closest  approximation of the cost per donut when one purchases a box of 6 ?\r<BR>\n" );
document.write( "\n" );
document.write( "a  $ 0.20    b  $0.30   c  $0.40   d  $0.50   e  $0.60   \r<BR>\n" );
document.write( "\n" );
document.write( "2)  what would be the least amount of money  needed to purchase exactly 21 donuts ?\r<BR>\n" );
document.write( "\n" );
document.write( "a  $5.88   b  $6.68   c  $7.19  d  $7.38   e  $8.40   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216523 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> which is the closest approximation of the cost per donut when one purchases a box of 6 ?<BR>\n" );
document.write( "a $ 0.20 b $0.30 c $0.40 d $0.50 e $0.60 \r<BR>\n" );
document.write( "\n" );
document.write( "box of 6 = $1.89\r<BR>\n" );
document.write( "\n" );
document.write( "$1.89 ÷ 6 = $ 0.315 \r<BR>\n" );
document.write( "\n" );
document.write( "round up = $ 0.3 \r<BR>\n" );
document.write( "\n" );
document.write( "Answer : (b) \r<BR>\n" );
document.write( "\n" );
document.write( "what would be the least amount of money needed to purchase exactly 21 donuts ?<BR>\n" );
document.write( "a $5.88 b $6.68 c $7.19 d $7.38 e $8.40 \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1 donuts - $0.40\r<BR>\n" );
document.write( "\n" );
document.write( "6 donuts - $1.89\r<BR>\n" );
document.write( "\n" );
document.write( "12 donuts - $3.59 \r<BR>\n" );
document.write( "\n" );
document.write( "21 donuts = 12 + 6 + 1 + 1 + 1 \r<BR>\n" );
document.write( "\n" );
document.write( "Cost = ($3.59) + ($1.89) + (3 x $0.4)<BR>\n" );
document.write( "= $6.68 \r<BR>\n" );
document.write( "\n" );
document.write( "Answer: (b)  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );