document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301937>Question 301937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you create a quadratic equation using 2 points already given to you? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216518 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If it's 2 points at random, it's not possible.  3 non-colinear points are necessary.<BR>\n" );
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document.write( "If the 2 points are the intersections with the same axis, eg:<BR>\n" );
document.write( "(3,0) and (5,0) then<BR>\n" );
document.write( "(x-3)*(x-5) = 0<BR>\n" );
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document.write( "(a,0) and (b,0) --> (x-a)*(x-b) = 0<BR>\n" );
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