document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301904>Question 301904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much would $300 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cent. Do not include units   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216511 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     How much would $300 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cent. Do not include units <BR>\n" );
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document.write( "Continuous compound interest formula:<BR>\n" );
document.write( "A = Pe^(rt)<BR>\n" );
document.write( "A is amount accumulated after t time<BR>\n" );
document.write( "P is initial amount<BR>\n" );
document.write( "r is rate or interest<BR>\n" );
document.write( "t is time<BR>\n" );
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document.write( "A = Pe^(rt)<BR>\n" );
document.write( "A = 300e^(.09*3)<BR>\n" );
document.write( "A = 300e^(.27)<BR>\n" );
document.write( "A = 392.99\r<BR>\n" );
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