document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301901>Question 301901</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't know how to use my computer keyboard to type the correct symbols so I will do it to the best of my ability so you can understand. As you can se this is a division problem.  ^=to the power of \r<BR>\n" );
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document.write( "y^2 + 7y - 18 / y^2 + 2y - 63 = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216494 by </B><A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><B>london maths tutor(243)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=london+maths+tutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=london+maths+tutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2 + 7y - 18 = (y+9)(y-2) \r<BR>\n" );
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document.write( "y^2 + 2y - 63 = (y-7)(y+9)\r<BR>\n" );
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document.write( "Therefore, \r<BR>\n" );
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document.write( "(y^2 + 7y - 18) / (y^2 + 2y - 63) = (y+9)(y-2) /(y-7)(y+9)\r<BR>\n" );
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document.write( "you can cancel (y+9) from the denominator and numerator \r<BR>\n" );
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document.write( "therefore the solution becomes :\r<BR>\n" );
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document.write( "(y-2)/(y-7)  </SPAN>\n" );
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