document.write( "Question 301905: If a bus is goin 60 kmph and it is delayed 3 hours but if it goes 90 kmph it is one hour early. How long is the route? \n" ); document.write( "
Algebra.Com's Answer #216484 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If it reaches on time let the number of hours be x \n" ); document.write( "Distance = rate * time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)*60=(x-1)*90\r \n" ); document.write( "\n" ); document.write( "60x+180=90x-90\r \n" ); document.write( "\n" ); document.write( "-30x=-270\r \n" ); document.write( "\n" ); document.write( "x=-270/-30\r \n" ); document.write( "\n" ); document.write( "x= 9 hours\r \n" ); document.write( "\n" ); document.write( "take any one of the speeds\r \n" ); document.write( "\n" ); document.write( "60 kmph it takes 3 hours more so it travels 12 hours \r \n" ); document.write( "\n" ); document.write( "12 *60 = 720 km\r \n" ); document.write( "\n" ); document.write( "90kmh it takes 1 hour less so itakes 8 hours\r \n" ); document.write( "\n" ); document.write( "8*90 =720 kms\r \n" ); document.write( "\n" ); document.write( "cheers \r \n" ); document.write( "\n" ); document.write( "Ananth \n" ); document.write( " |