document.write( "Question 301746: 6x+y=44
\n" ); document.write( "6x+7y=28 \r
\n" ); document.write( "\n" ); document.write( "I do it this way correct:
\n" ); document.write( "6x+7y(44-6x)=28
\n" ); document.write( "6x=308-42x=28
\n" ); document.write( "48x+308=28
\n" ); document.write( "co efficient is 48
\n" ); document.write( "48x+308=28
\n" ); document.write( "48x-336
\n" ); document.write( "x=7
\n" ); document.write( "y=44 -6(7x)
\n" ); document.write( "44-42
\n" ); document.write( "y = 2 \n" ); document.write( "
Algebra.Com's Answer #216366 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
6x+y=44
\n" ); document.write( "6x+7y=28
\n" ); document.write( "----
\n" ); document.write( "An easier way to do it.
\n" ); document.write( "Subtract the 1st Eq. from the 2nd, and solve for \"y\":
\n" ); document.write( "6y = -16
\n" ); document.write( "y = -8/3
\n" ); document.write( "---------
\n" ); document.write( "Substitute for y in the 1st Eq. and solve for \"x\":
\n" ); document.write( "6x + (-8/3) = 44
\n" ); document.write( "6x = (132/3)+(8/3)
\n" ); document.write( "6x = 140/3
\n" ); document.write( "x = 140/18
\n" ); document.write( "x = 70/9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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