document.write( "Question 301736: a total of $10000 was invested in to simple intrest accounts for one year. the first account has an 8% intrest rate, the second account has a 9% intrest rate. if the total intrest of the 2 accounts in one year was $840 how much was invested in each account \n" ); document.write( "
Algebra.Com's Answer #216352 by JBarnum(2146)\"\" \"About 
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\"F%2BS=10000\" F=amount of money invested in First account, S=amount of money invested in Second account
\n" ); document.write( "\".08F%2B.09S=840\" 8%=.08 9%=.09
\n" ); document.write( "u can use substitution or elimination method i will use elimination method as its faster.
\n" ); document.write( "\"F%2BS=10000\" multiply this by -.08
\n" ); document.write( "\".08F%2B.09S=840\"
\n" ); document.write( "_________________
\n" ); document.write( "\"-.08F-.08S=-800\"
\n" ); document.write( "\".08F%2B.09S=840\"add the equations together
\n" ); document.write( "\".01S=40\"
\n" ); document.write( "\"S=4000\"
\n" ); document.write( "_______
\n" ); document.write( "\"F%2BS=10000\"
\n" ); document.write( "\"F%2B4000=10000\"
\n" ); document.write( "\"F=6000\"
\n" ); document.write( "first account has 6000
\n" ); document.write( "second account has 4000
\n" ); document.write( "
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