document.write( "Question 35485: Find the exact values for the trig functions, with the radian measure:\r\n" );
document.write( " 15p/4
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document.write( "
Algebra.Com's Answer #21626 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! ANGLE =15*PI/4=16*PI/4-PI/4=-PI/4....THAT IS WE TAKE TRIANGLE WITH ANGLE PI/4 AND APPLY THE RULE OF SIGNS...\"ALL SILVER TEA CUPS\"...THAT IS IT IS AN ISOCELLES RIGHT ANGLED TRIANGLE.HENCE LET BOTH SIDES BE 1 EACH. THEN HYPOTENUSE =SQRT(1^2+1^2)=SQRT(2) \n" ); document.write( "SO \n" ); document.write( "SIN (PI/4)=1/SQRT(2)=SQRT(2)/2=1.4142/2=0.7071 \n" ); document.write( "COSEC(PI/4)=SQRT(2)=1.4142 \n" ); document.write( "COS(PI/4)= 1/SQRT(2)=SQRT(2)/2=1.4142/2=0.7071 \n" ); document.write( "SEC(PI/4)=SQRT(2)=1.4142 \n" ); document.write( "TAN(PI/4)=1/1=1 \n" ); document.write( "COT(PI/4)=1/1=1\r \n" ); document.write( "\n" ); document.write( "HENCE \r \n" ); document.write( "\n" ); document.write( "SIN (-PI/4)=-1/SQRT(2)=-SQRT(2)/2=-1.4142/2=-0.7071 \n" ); document.write( "COSEC(-PI/4)=-SQRT(2)=-1.4142 \n" ); document.write( "COS(-PI/4)= 1/SQRT(2)=SQRT(2)/2=1.4142/2=0.7071 \n" ); document.write( "SEC(-PI/4)=SQRT(2)=1.4142 \n" ); document.write( "TAN(-PI/4)=-1/1=-1 \n" ); document.write( "COT(-PI/4)=-1/1=-1 \n" ); document.write( " |