document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34016>Question 34016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi.  How would I figure out the surface area for a right square pyramid with a length of 6.5 cm and the base being 2.5 cm?  \r<BR>\n" );
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document.write( "I'm a little confused because on each triangular surface, it says 2.5 cm on each half.  Does that mean I need to add them for each side, equalling 5 cm on each side?  \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21623 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi. How would I figure out the surface area for a right square pyramid with a length of 6.5 cm<BR>\n" );
document.write( "OK...THIS MEANS BASE IS A SQUARE OF SIDE LENGTH 6.5 CM EACH <BR>\n" );
document.write( " and the base being 2.5 cm?<BR>\n" );
document.write( "THERE IS SOME THING WRONG HERE.IT IS NOT BASE.IT HAS NO MEANING.IT CAN BE ALTITUDE OR SLANT HEIGHT.PLEASE CHECKUP.<BR>\n" );
document.write( "I'm a little confused because on each triangular surface, it says 2.5 cm on each half.?<BR>\n" );
document.write( "WHAT IS THIS AGAIN?PLEASE COPY PROBLEM PROPERLY AS IT IS IN THE BOOK OR WHATEVER SOURCE IF YOU WANT US TO SOLVE IT<BR>\n" );
document.write( " Does that mean I need to add them for each side, equalling 5 cm on each side? </SPAN>\n" );
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