document.write( "Question 301568: The second angle of a triangle is twice the first angle. The third angle is five more than four times the first angle. What is the measure of the second angle?\r
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Algebra.Com's Answer #216216 by mananth(16946)\"\" \"About 
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let the first angle be x \r
\n" ); document.write( "\n" ); document.write( "the second angle will be 2x\r
\n" ); document.write( "\n" ); document.write( "the third abgle = 4x+5\r
\n" ); document.write( "\n" ); document.write( "THE SUM OF ALL THE ANGLES OF A TRIANGLE = 180 DEG\r
\n" ); document.write( "\n" ); document.write( "x+2x+4x+5=180\r
\n" ); document.write( "\n" ); document.write( "7x+5=180
\n" ); document.write( "7x= 180-5
\n" ); document.write( "x=175/7\r
\n" ); document.write( "\n" ); document.write( "x= 25 the first angle\r
\n" ); document.write( "\n" ); document.write( "second angle = 2x = 50 deg\r
\n" ); document.write( "\n" ); document.write( "theird angle = 4x +5 = 4*25 +5=105 deg\r
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