document.write( "Question 301290: Trains A and B are traveling in the same diection on parallel tracks. A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour .Train A passes the station at 5:15am .If train B passs the same station at 5:27 a.m.at what time will train be catch at to train A. When will train b catch up with train A? \n" ); document.write( "
Algebra.Com's Answer #216194 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same diection on parallel tracks. \n" ); document.write( " A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour Train A passes the station at 5:15am . \n" ); document.write( "If train B passes the same station at 5:27 a.m. at what time will train B catch at to train A. \n" ); document.write( "When will train B catch up with train A? \n" ); document.write( ": \n" ); document.write( "from the given information, we know that train B is 12 min (1/5 hr) behind \n" ); document.write( " train A, when train A passes the station \n" ); document.write( ": \n" ); document.write( "The distance between the trains at this time: \n" ); document.write( ": \n" ); document.write( "Let t = time required for train B to catch train A \n" ); document.write( ": \n" ); document.write( "write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "Train B travel dist = Train A travel dist + 20 mi \n" ); document.write( "100t = 80t + 20 \n" ); document.write( "100t - 80t = 20 \n" ); document.write( "20t = 20 \n" ); document.write( "t = \n" ); document.write( "t = 1 hr \n" ); document.write( ": \n" ); document.write( "5:15 + 1:00 = 6:00 AM, B catches A \n" ); document.write( " |