document.write( "Question 301441: What would be the dimension of a rectangle if the area is 12 and the perimeter is 16? \n" ); document.write( "
Algebra.Com's Answer #216187 by checkley77(12844)\"\" \"About 
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12=LW OR L=12/W FOR THE AREA.
\n" ); document.write( "2L+2W=16 FOR THE PERIMETER.
\n" ); document.write( "2(12/W)+2W=16
\n" ); document.write( "24/W+2W=16
\n" ); document.write( "(24+2W*W)/W=16
\n" ); document.write( "(24+2W^2)/W=16
\n" ); document.write( "24+2W^2=16W
\n" ); document.write( "2W^2-16W+24=0
\n" ); document.write( "2(W^2-8W+12)=0
\n" ); document.write( "2(W-6)(W-2)=0
\n" ); document.write( "W-6=0
\n" ); document.write( "W=6 ans. L=12/6=2 ANS.
\n" ); document.write( "W-2=0
\n" ); document.write( "W=2 ANS. L=12/2=6 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*6=12
\n" ); document.write( "12=12
\n" ); document.write( "2*2+2*6=16
\n" ); document.write( "4+12=16
\n" ); document.write( "16=16
\n" ); document.write( " \n" ); document.write( "
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