document.write( "Question 35133: We are working on combinations and permutaions which involve factorials most of the time.\r
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document.write( "How many 4 letter combinations can be made from the letters f,g,h,i,j & k. No letters can repeat themselves and the letter do not have to form a word. How do you solve this? \n" );
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Algebra.Com's Answer #21613 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! We are working on combinations and permutaions which involve factorials most of the time. \n" ); document.write( "How many 4 letter combinations can be made from the letters f,g,h,i,j & k. No letters can repeat themselves and the letter do not have to form a word. How do you solve this? \n" ); document.write( "COUNT TOTAL NUMBER OF LETTERS=6 \n" ); document.write( "TO MAKE 4 LETTER COMBINATIONS YOU SAID THAT IS NOT PROPER I THINK..THAT MEANS A TEAM OF 4 PLAYERS FROM 6 PERSONS.THAT MEANS ABCD..OR...BCDA...OR...CDBA..ETC...ARE ALL SAME TEAM.THE ARRANGEMENT IS NOT IMPORATANT.THEN ONLY IT IS CALLED COMBINATION.THEN THE ANSWER IS 6C4..THE FOMULA FOR NCR = N!/{(R!)*(N-R)!} \n" ); document.write( "SO WE GET 6!/2!*(4-2)!=6!/2!*4!=6*5*4*3*2*1/2*1*4*3*2*1=15... \n" ); document.write( "BUT I THINK YOU WANT ARRANGEMENTS .THEN ITS ANSWER IS 6P4..THE FORMULA FOR \n" ); document.write( "NPR=N!/(N-R)! \n" ); document.write( "6P4=6!/(6-4)!=6!/2!=360 \n" ); document.write( " |