document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301413>Question 301413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve 4xsqared-16x+3=0 by using completing the square   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216105 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 4x^2\ -\ 16x\ +\ 3\ =\ 0\">\r<BR>\n" );
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document.write( "Step 1:  Divide through by the lead coefficient:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ +\ \frac{3}{4}\ =\ 0\">\r<BR>\n" );
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document.write( "Step 2:  Add the Additive Inverse of the Constant term to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ =\ -\frac{3}{4}\">\r<BR>\n" );
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document.write( "Step 3:  Divide the coefficient of the first degree term by 2, square the result, and add that result to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{-4}{2}\right)^2\ =\ 4\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ +\ 4\ =\ -\frac{3}{4}\ +\ 4\">\r<BR>\n" );
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document.write( "Step 4: Factor the perfect square in the LHS and simplify the RHS:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ 2\right)^2\ =\ \frac{13}{4}\">\r<BR>\n" );
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document.write( "Step 5: Take the square root of both sides, remembering to consider both the positive and negative root\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 2\ =\ \pm\sqrt{\frac{13}{4}}\ =\ \frac{\pm\sqrt{13}}{2}\">\r<BR>\n" );
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document.write( "Step 6: Finish solving:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 2 +\frac{\pm\sqrt{13}}{2}\ =\ \frac{4\ \pm\ \sqrt{13}}{2}\">\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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