document.write( "Question 301358: A 60% acid solution is to be mixed with a
\n" ); document.write( "80% acid solution to produce 20 Liters of a
\n" ); document.write( "65% acid solution. How many liters of each
\n" ); document.write( "solution is needed?
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Algebra.Com's Answer #216058 by josmiceli(19441)\"\" \"About 
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Let \"a\" = liters of 60% solution needed
\n" ); document.write( "Let \"b\" = liters of 80% solution needed
\n" ); document.write( "given:
\n" ); document.write( "(1) \"a+%2B+b+=+20\" liters
\n" ); document.write( "\".6a+%2B+.8b+=+.65%2A20\"
\n" ); document.write( "\".6a+%2B+.8b+=+13\"
\n" ); document.write( "(2) \"6a+%2B+8b+=+130\"
\n" ); document.write( "Multiply both sides of (1) by \"6\" and subtract (1) from (2)
\n" ); document.write( "\"6a+%2B+8b+=+130\"
\n" ); document.write( "\"-6a+-+6b+=+-120\"
\n" ); document.write( "\"2b+=+10\"
\n" ); document.write( "\"b+=+5\"
\n" ); document.write( "and, since
\n" ); document.write( "\"a+%2B+b+=+20\"
\n" ); document.write( "\"a+%2B+5+=+20\"
\n" ); document.write( "\"a+=+15\"
\n" ); document.write( "15 liters of 60% solution and 5 liters of 80% solution are needed
\n" ); document.write( "check:
\n" ); document.write( "In words:
\n" ); document.write( "(liters of acid you end up with) / (final total liters of solution) = 65%
\n" ); document.write( "\"%28.6%2A15+%2B+.8%2A5%29%2F20+=+.65\"
\n" ); document.write( "\"9+%2B+4+=+.65%2A20\"
\n" ); document.write( "\"13+=+13\"
\n" ); document.write( "OK
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