document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301316>Question 301316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve: using substitution <BR>\n" );
document.write( "5x-2y=-7<BR>\n" );
document.write( "8=y-4x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #216049 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=216049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you have to rearrange the second.<BR>\n" );
document.write( "4x+8=y<BR>\n" );
document.write( "now plug 4x+8 for y in the first<BR>\n" );
document.write( "5x-2*(4x+8)=-7<BR>\n" );
document.write( "5x-8x-16=-7<BR>\n" );
document.write( "-3x=9<BR>\n" );
document.write( "x=-3<BR>\n" );
document.write( "now plug that into the second and solve for y<BR>\n" );
document.write( "8=y-4*(-3)<BR>\n" );
document.write( "8=y+12<BR>\n" );
document.write( "-4=y<BR>\n" );
document.write( "(x,y)=(-3,-4)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );