document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35378>Question 35378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x^-1+y^-1)/(x^-1y)   I tried this, but just not sure.\r<BR>\n" );
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document.write( "I cancelled out the x^-1, and that left me with y^-1/y wich  I believe is (1/y)/(y) can you tell me if this is right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21601 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The x^-1 in the numerator is a TERM, since it is added to they y^-1.  NEVER DIVIDE OUT TERMS!!  ONLY FACTORS!!  See the solution that I previously posted for the correct solution to this.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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