document.write( "Question 301256: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
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document.write( "A rectangular blanket is 20 inches longer than it is wide. If the area of the blanket is 1,125 square inches, find the length and the width. Show work
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document.write( "i think this one is l*w*h but some one please tell me for sure \n" );
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Algebra.Com's Answer #215993 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution. \n" ); document.write( "A rectangular blanket is 20 inches longer than it is wide. If the area of the blanket is 1,125 square inches, find the length and the width. Show work \n" ); document.write( "i think this one is l*w*h but some one please tell me for sure \n" ); document.write( "Let the width be x\r \n" ); document.write( "\n" ); document.write( "the length will be x+20\r \n" ); document.write( "\n" ); document.write( "Area of rectangle = L*W\r \n" ); document.write( "\n" ); document.write( "x*(x+20)= 1125\r \n" ); document.write( "\n" ); document.write( "x^2+20x=1125 \n" ); document.write( "x^2+20x-1125=0\r \n" ); document.write( "\n" ); document.write( "x^2+45x-25x-1125=0\r \n" ); document.write( "\n" ); document.write( "x(x+25)-25(x+45)=0\r \n" ); document.write( "\n" ); document.write( "(x-25)(x+45)=0\r \n" ); document.write( "\n" ); document.write( "x= 25 OR -45\r \n" ); document.write( "\n" ); document.write( "the width cant be -ve value\r \n" ); document.write( "\n" ); document.write( "so width = 25 inches\r \n" ); document.write( "\n" ); document.write( "Length will be 25+20 =45 Inches\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |